Conservation of Momentum (GCSE Physics)
Conservation of Momentum
Conservation of Momentum
Momentum is a very important concept in Physics, and it is a property of all moving objects.
There is a key principle that you should know in relation to this topic – the conservation of momentum:
In a closed system, the total momentum before an event is equal to the total momentum after the event.
Closed and Open Systems
This principle is for a closed system. Remember, a closed system is one which does not exchange energy with the surroundings.
In real life, if there was a car crash, for example, it would be an open system so lots of energy would be lost as heat and sound energy to the surroundings. However, in exams we will normally be assuming that it is a closed system to make calculations easier.
![Conservation of Momentum](https://studymind.co.uk/wp-content/uploads/2022/05/1-197.png)
Examples of Momentum
Qualitative Scenarios of Momentum
Below we will practice some examples of momentum calculations.
Example Scenario: Imagine two skaters on an ice rink. Skater A is stationary, whilst Skater B is moving with a velocity. Skater B collides into Skater A, causing both skaters to move off together with a lower velocity. Momentum is conserved.
In this scenario, momentum has been conserved.
Momentum Before Collision
Before the two skaters collided, the momentum is: Mass of Skater B x Velocity. We do not take into account A, because it cannot have a momentum as it has a velocity of 0.
![Conservation of Momentum](https://studymind.co.uk/wp-content/uploads/2022/05/2-137.png)
Momentum After Collision
After the collision, the momentum is: (Mass of A + B) x Velocity. The mass of the system will have increased because it is now (A + B) rather than just B. If momentum is to stay the same, the velocity must decrease.
![Conservation of Momentum](https://studymind.co.uk/wp-content/uploads/2022/05/3-93.png)
Quantitative Scenarios of Momentum
In exams, you may be asked to perform calculations involving momentum. We can elaborate on the previous example to demonstrate this.
Question: Imagine two skaters on an ice rink. Skater A (mass 45 kg) is stationary, whilst Skater B (mass of 60kg) is moving with a velocity of 6 m/s. Skater B collides into Skater A, causing both skaters to move off together with a lower velocity. Assuming that momentum is conserved, what is the new lower velocity, to 1 d.p.?
1. Draw a diagram.
![Conservation of Momentum](https://studymind.co.uk/wp-content/uploads/2022/05/4-61.png)
2. Calculate initial momentum.
This is the momentum before the collision occurs.
Initial momentum = mass x velocity
Initial momentum = 60 x 6
Initial momentum = 360 kg m/s
3. Calculate the final momentum.
We do not know the velocity, so we can substitute this with the symbol ‘v’.
Final momentum = mass x velocity
We need to calculate the total mass of both skaters when they move off
together.
This is 45 + 60 = 105 kg.
Final momentum = 105 x v
4. Find ‘v’.
By using the concept of conservation of momentum, we know that the initial momentum = final momentum. We can use this to find ‘v’.
Initial momentum = Final momentum
360 = 105 x v
v = 360 / 105
v = 3.428571
v = 3.4 m/s (1dp)
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